(2x^2+3x-2)-(2x^2+3)=19

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Solution for (2x^2+3x-2)-(2x^2+3)=19 equation:


Simplifying
(2x2 + 3x + -2) + -1(2x2 + 3) = 19

Reorder the terms:
(-2 + 3x + 2x2) + -1(2x2 + 3) = 19

Remove parenthesis around (-2 + 3x + 2x2)
-2 + 3x + 2x2 + -1(2x2 + 3) = 19

Reorder the terms:
-2 + 3x + 2x2 + -1(3 + 2x2) = 19
-2 + 3x + 2x2 + (3 * -1 + 2x2 * -1) = 19
-2 + 3x + 2x2 + (-3 + -2x2) = 19

Reorder the terms:
-2 + -3 + 3x + 2x2 + -2x2 = 19

Combine like terms: -2 + -3 = -5
-5 + 3x + 2x2 + -2x2 = 19

Combine like terms: 2x2 + -2x2 = 0
-5 + 3x + 0 = 19
-5 + 3x = 19

Solving
-5 + 3x = 19

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 3x = 19 + 5

Combine like terms: -5 + 5 = 0
0 + 3x = 19 + 5
3x = 19 + 5

Combine like terms: 19 + 5 = 24
3x = 24

Divide each side by '3'.
x = 8

Simplifying
x = 8

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